Controversial Do you believe in the existence of a flat earth?
- Thread starter Bob74h
- Start date
think about it though think about it
gravity? government conspiracy to stop people from questioning whats really going on
Agartha is real, they are hiding it because our leaders are from there. IF people find out about it, we will all be genocided or converted to Satanism.
The spherical projection is to hide the truth,
the moon landing? Fake.
satelittes? dont exist.
But some question why any government would bother.... well the truth is simple. Once they dillude people into believing the OBVIOUS lies right in front of them, they'll have complete control.
PROOF EARTH FLAT!
surface area of the part of the sphere x2+y2+z2=1 that is inside the cylinder x2+y2=1/4.
This problem is harder because it requires you to use a triple integral. A triple integral is an integral that is used to calculate the volume of a three-dimensional region.
The solution to this problem is as follows:
The surface area of the part of the sphere x2+y2+z2=1 that is inside the cylinder x2+y2=1/4 is given by:
S = \int_0^{2\pi} \int_0^{1/2} \sqrt{1 - \left( \frac{x}{2} \right)^2} , dx , d\theta = 2\pi \sqrt{3}/4
This integral can be evaluated using the following steps:
S = \int_0^{2\pi} \int_0^{1/2} \sqrt{1 - r^2} \, r \, dr \, d\theta
S = 2\pi \int_0^{2\pi} \frac{\sqrt{1 - r^2}}{2} \, dr \, d\theta
S = 2\pi \sqrt{3}/4
Therefore, the surface area of the part of the sphere x2+y2+z2=1 that is inside the cylinder x2+y2=1/4 is given by:
S = 2\pi \sqrt{3}/4
WHICH DOESNT WORK!!!!!!!!!!!!!!!!!!!!!
gravity? government conspiracy to stop people from questioning whats really going on
Agartha is real, they are hiding it because our leaders are from there. IF people find out about it, we will all be genocided or converted to Satanism.
The spherical projection is to hide the truth,
the moon landing? Fake.
satelittes? dont exist.
But some question why any government would bother.... well the truth is simple. Once they dillude people into believing the OBVIOUS lies right in front of them, they'll have complete control.
PROOF EARTH FLAT!
surface area of the part of the sphere x2+y2+z2=1 that is inside the cylinder x2+y2=1/4.
This problem is harder because it requires you to use a triple integral. A triple integral is an integral that is used to calculate the volume of a three-dimensional region.
The solution to this problem is as follows:
The surface area of the part of the sphere x2+y2+z2=1 that is inside the cylinder x2+y2=1/4 is given by:
S = \int_0^{2\pi} \int_0^{1/2} \sqrt{1 - \left( \frac{x}{2} \right)^2} , dx , d\theta = 2\pi \sqrt{3}/4
This integral can be evaluated using the following steps:
S = \int_0^{2\pi} \int_0^{1/2} \sqrt{1 - r^2} \, r \, dr \, d\theta
S = 2\pi \int_0^{2\pi} \frac{\sqrt{1 - r^2}}{2} \, dr \, d\theta
S = 2\pi \sqrt{3}/4
Therefore, the surface area of the part of the sphere x2+y2+z2=1 that is inside the cylinder x2+y2=1/4 is given by:
S = 2\pi \sqrt{3}/4
WHICH DOESNT WORK!!!!!!!!!!!!!!!!!!!!!
